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Chapter 6.2 (Length of a Curve) Additional Resources

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Videos (Pg. 280-282)

Khan Academy
Professor Leonard
Krista King

Outside Notes

Lamar
Dummies

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Webassign HW 03 6.4 - Answers/Explanations

Remember in the Webassign section there are other answer sets just not explanations! For this problem, remember the basic formula for work is the integral of the force equation. This problem is 2000 is the force equation and 1152 feet is the upper bound with 0 being the lower bound. For this problem, problem gives you the initial bounds and force equation. Again, this simply typing in the inputs. REMEMBER you dx! To solve the integral, take out the 1000 and factor the remaining function. Next using the law of sums break the integral up and solve each separately adding the results together at the end. Or use Symbolab . For this one, remember the Spring equations. First work equals the integral of the spring constant and X. Also, force equals the spring constant times X (displacement). To begin, the person stretches the spring 11 cm at a force of 2200 dynes (dynes is a measure of force). Then he stretches it 11 more cm. First, the initial 11cm is the bottom bound becaus...

Webassign HW 02 6.1 - Answers/Explanations

Remember in the Webassign section there are other answer sets just not explanations! This type of problem is best described as a square cylinder centered at the origin. The problem gives that the cross-sections are square so x^2 is equal to the area of any given cross-section. However, they note the side length in terms of radius so you need to multiplied by two. So 2x represents one length of the square and 4x^2 the area of the corresponding cross-section. Now because the base is a circle, the cross-sections will change depending on how close to the origin you are because of this you need to find an equation of x to represent the length of a side. In this case, the radius is largest (3 units) at the origin and smallest at plus of minus three units from the origin (0 units). You need to consider how as you travel across the x-axis of the circular base how y is affected. Once you do this you can devise that 4(9-x^2) is the formula. From here, you need to remember you placed...

Chapter 6.5 (Moments and Center of Gravity) Additional Resources

Moments of Point Masses and Moments of Plane Regions about the X Axis (Pg. 400-404) Videos MathemAddicts (Parts 1 and 2) Krista King Outside Notes EmathHelp Lamar Whiteman Theorem of Pappus and Guldin (Pg. 404-405) Videos Khan Academy Krista King There isn't many relevant resources I could find. Please email me anything that may be helpful at PassMath141@gmail.com.

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